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Post by slippy0 on Mar 13, 2006 21:41:55 GMT -5
Wait... just kidding, it would be 26.565... hold on... dinner... you where right about how the perp. bis. wouldn't intersect the far point unless it was equilateral, which it isn't. Which makes the whole problem wrong. Unless Getz knows something we don't... |
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Post by GetZ on Mar 13, 2006 22:04:28 GMT -5
Yeah, my answer is wrong also because it still depends on the assumption that I made, which was initially for the purpose of simplifying the problem but then I forgot that I made that assumption and worked out an incorrect solution.  Anyways, I do have a somewhat lame way of solving it exactly but I want to try out a couple of other things on it too (just for fun). I'll see if I can find a scanner at school tomorrow so that I can just scan a written solution instead of typing it on the comp. For now, i'm off to bed. Got an early day tomorrow. |
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Post by Captain Awesome on Mar 13, 2006 22:04:34 GMT -5
I get 7.9999, which is wrong (I think?). I think I need to extend my decimals more... Hmmm. EDIT:I'll see if I can find a scanner at school tomorrow so that I can just scan a written solution instead of typing it on the comp. Yeah, I did most of my calculations on graph paper. It'd be nice to just post that up here. |
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Post by mattis on Mar 13, 2006 22:17:46 GMT -5
TeXaide. then screenshot, then hosting. good for all your equation-typing needs! 
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Post by GetZ on Mar 14, 2006 20:28:48 GMT -5
I didn’t find a scanner today but I do have the solution. The answer is 8 (exactly) and it's obtained by the way that I initially started out with before going coo coo. So my own personal lesson from this is: Don't second guess my self. I'll try and scan it tomorrow afternoon but if I can't find one i'll use teXaide (thanks mattis  in the evening.. |
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Post by slippy0 on Mar 14, 2006 20:49:17 GMT -5
I didn’t find a scanner today but I do have the solution. The answer is 8 (exactly) and it's obtained by the way that I initially started out with before going coo coo. So my own personal lesson from this is: Don't second guess my self. I'll try and scan it tomorrow afternoon but if I can't find one i'll use teXaide (thanks mattis in the evening.. well I'll be look foreward to seeing this |
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Post by Kevin on Mar 14, 2006 22:28:16 GMT -5
Bwahaha I was right... my AutoCAD skills are 1337.
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Post by mattis on Mar 15, 2006 17:06:54 GMT -5
basic graph stuff.
y=(x+2)2
y=-x2+4
these lines intersect at two points. find the distance between the two points and give your answer in simplest radical form.
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Post by slippy0 on Mar 15, 2006 19:20:54 GMT -5
basic graph stuff. y=(x+2) 2y=-x 2+4 these lines intersect at two points. find the distance between the two points and give your answer in simplest radical form. may I ask, what does that have to do with anything |
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Post by GetZ on Mar 15, 2006 19:22:14 GMT -5
That's how slippy0's problem is solved: Solution While at class today I think I figured out why they don't have scanners just laying around in the computer labs for just anyone to use at any time... young adults... yeah, can you imagine the pranks and stuff ;D So I used a digital camera instead. Down in the middle those are just arrows going from one step to another, which leads to using the quadratic formula which in turn pops out two results. The quality of the image is'nt that great but I think it's still functional... |
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Post by mattis on Mar 15, 2006 19:40:07 GMT -5
it has to do with math, which we were just talking about. although it's not an acheivement. |
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Post by slippy0 on Mar 15, 2006 20:20:19 GMT -5
That's how slippy0's problem is solved: Solution While at class today I think I figured out why they don't have scanners just laying around in the computer labs for just anyone to use at any time... young adults... yeah, can you imagine the pranks and stuff ;D So I used a digital camera instead. Down in the middle those are just arrows going from one step to another, which leads to using the quadratic formula which in turn pops out two results. The quality of the image is'nt that great but I think it's still functional... wow. I love seeing that brilliant glimpse of insight that lets us find these solutions. Yours was simply considering the circle a function on the plane, and found intersection. Great job ;D Mattis: y=(x+2)2 y=-x2+4 (x+2)(x+2)=(2-x)(2+x) <-- (from this we get x=-2) x+2=2-x x=-x 2x=0 x=0 plug it in and you get the cord. (-2,0) and (0,4) sqrt(2 2+4 2)=sqrt(20)=sqrt(2*2*5) =2*sqrt(5) |
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Post by Blastgirl on Mar 15, 2006 21:24:31 GMT -5
Oh yeah everybody knows that ;D
I'm kidding. It's great that you guys are so good at obstract math.
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